16x^2-48x-864=0

Solution for 16x^2-48x-864=0 equation:

16x^2-48x-864=0

a = 16; b = -48; c = -864;
Δ = b2-4ac
Δ = -482-4·16·(-864)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-240}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+240}{2*16}=\frac{288}{32}
=9
$